(3x-10)+(4x^2-3x+12)=

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Solution for (3x-10)+(4x^2-3x+12)= equation:


Simplifying
(3x + -10) + (4x2 + -3x + 12) = 0

Reorder the terms:
(-10 + 3x) + (4x2 + -3x + 12) = 0

Remove parenthesis around (-10 + 3x)
-10 + 3x + (4x2 + -3x + 12) = 0

Reorder the terms:
-10 + 3x + (12 + -3x + 4x2) = 0

Remove parenthesis around (12 + -3x + 4x2)
-10 + 3x + 12 + -3x + 4x2 = 0

Reorder the terms:
-10 + 12 + 3x + -3x + 4x2 = 0

Combine like terms: -10 + 12 = 2
2 + 3x + -3x + 4x2 = 0

Combine like terms: 3x + -3x = 0
2 + 0 + 4x2 = 0
2 + 4x2 = 0

Solving
2 + 4x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 4x2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 4x2 = 0 + -2
4x2 = 0 + -2

Combine like terms: 0 + -2 = -2
4x2 = -2

Divide each side by '4'.
x2 = -0.5

Simplifying
x2 = -0.5

Reorder the terms:
0.5 + x2 = -0.5 + 0.5

Combine like terms: -0.5 + 0.5 = 0.0
0.5 + x2 = 0.0

The solution to this equation could not be determined.

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